-16x^2+80x-36=0

Solution for -16x^2+80x-36=0 equation:

-16x^2+80x-36=0

a = -16; b = 80; c = -36;
Δ = b2-4ac
Δ = 802-4·(-16)·(-36)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-64}{2*-16}=\frac{-144}{-32}
=4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+64}{2*-16}=\frac{-16}{-32}
=1/2
$